The ratio of the weight of a man in a stationary lift & when it is moving downward with uniform acceleration 'a' is 3: 2. The value of 'a' is: (g = acceleration. due to gravity)
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Verified by ExpertsThe correct answer is:
D
Weight of man in stationary lift is mg.
mg – N = ma [Newton’s II law for man]
N =m (g – a)
Weight of man in moving lift is equal to N.
a = 
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